kider 发表于 2007-12-3 17:37:25

简单查询树形结构数据库表

作者: 简单,  出处:博客园

  在与同事Rock讨论中,得到一个思路,不用嵌套调用直接用一个语句就可以生成树,实事上他已经做好了该程序,他用了临时表写了一个存储过程,我改写为一个表值函数,供大家参考:
  表结构及表值函数如下:
  查询树表语句

1/**//****** Object: Table . Script Date: 2005-11-04 18:07:00 ******/
2CREATE TABLE . (
3 IDENTITY (1, 1) NOT NULL ,
4 NULL ,
5 (10) COLLATE Chinese_PRC_CI_AS NULL
6) ON
7GO
8
9 CREATE CLUSTERED INDEX ON .() ON
10GO
11
12ALTER TABLE . WITH NOCHECK ADD
13 CONSTRAINT PRIMARY KEY NONCLUSTERED
14 (
15
16 ) ON ,
17 CONSTRAINT [子ID不能等于父ID] CHECK ( <> )
18GO
19
20ALTER TABLE . ADD
21 CONSTRAINT FOREIGN KEY
22 (
23
24 ) REFERENCES . (
25
26 )
27GO
28
29/**//****** 对象: 用户定义的函数 dbo.fGetTreeTable 脚本日期: 2005-11-04 18:07:02 ******/
30CREATE FUNCTION dbo.fGetTreeTable
31 (
32 @ID int= null
33 )
34RETURNS @Tab TABLE(ID int, PID int, Name varchar(10), Lev int)
35AS
36 BEGIN
37 Declare @lev int
38 Set @lev=0
39
40 While @lev=0 or @@ROWCount>0
41 Begin
42 Set @Lev=@Lev+1
43 Insert @Tab(ID, PID, Name, Lev)
44 Select ID, PID, Name, @Lev From Tree Where (@Lev=1 and ((PID=@ID) or (@ID is null and PID is null))) or (PID in (Select ID From @Tab Where Lev=@Lev-1))
45 order by ID
46 End
47 RETURN
48 END
49
50GO
51
52--实际数据
53Insert Tree(PID, Name) values(null, 公司)
54Insert Tree(PID, Name) values(3, IT)
55Insert Tree(PID, Name) values(1, Fin)
56Insert Tree(PID, Name) values(5, XZ)
57Insert Tree(PID, Name) values(1, HR)
58GO

直接查询Select * from dbo.fGetTreeTable(null)就可以输入所有记录。
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